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/*-
* Copyright (c) 2011 David Schultz
* All rights reserved.
*
* Redistribution and use in source and binary forms, with or without
* modification, are permitted provided that the following conditions
* are met:
* 1. Redistributions of source code must retain the above copyright
* notice unmodified, this list of conditions, and the following
* disclaimer.
* 2. Redistributions in binary form must reproduce the above copyright
* notice, this list of conditions and the following disclaimer in the
* documentation and/or other materials provided with the distribution.
*
* THIS SOFTWARE IS PROVIDED BY THE AUTHOR ``AS IS'' AND ANY EXPRESS OR
* IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES
* OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED.
* IN NO EVENT SHALL THE AUTHOR BE LIABLE FOR ANY DIRECT, INDIRECT,
* INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT
* NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
* DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
* THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
* (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF
* THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
*/
/*
* Hyperbolic tangent of a complex argument z = x + I y.
*
* The algorithm is from:
*
* W. Kahan. Branch Cuts for Complex Elementary Functions or Much
* Ado About Nothing's Sign Bit. In The State of the Art in
* Numerical Analysis, pp. 165 ff. Iserles and Powell, eds., 1987.
*
* Method:
*
* Let t = tan(x)
* beta = 1/cos^2(y)
* s = sinh(x)
* rho = cosh(x)
*
* We have:
*
* tanh(z) = sinh(z) / cosh(z)
*
* sinh(x) cos(y) + I cosh(x) sin(y)
* = ---------------------------------
* cosh(x) cos(y) + I sinh(x) sin(y)
*
* cosh(x) sinh(x) / cos^2(y) + I tan(y)
* = -------------------------------------
* 1 + sinh^2(x) / cos^2(y)
*
* beta rho s + I t
* = ----------------
* 1 + beta s^2
*
* Modifications:
*
* I omitted the original algorithm's handling of overflow in tan(x) after
* verifying with nearpi.c that this can't happen in IEEE single or double
* precision. I also handle large x differently.
*/
#include <sys/cdefs.h>
__FBSDID("$FreeBSD: head/lib/msun/src/s_ctanh.c 284427 2015-06-15 20:40:44Z tijl $");
#include <complex.h>
#include <math.h>
#include "math_private.h"
double complex
ctanh(double complex z)
{
double x, y;
double t, beta, s, rho, denom;
uint32_t hx, ix, lx;
x = creal(z);
y = cimag(z);
EXTRACT_WORDS(hx, lx, x);
ix = hx & 0x7fffffff;
/*
* ctanh(NaN +- I 0) = d(NaN) +- I 0
*
* ctanh(NaN + I y) = d(NaN,y) + I d(NaN,y) for y != 0
*
* The imaginary part has the sign of x*sin(2*y), but there's no
* special effort to get this right.
*
* ctanh(+-Inf +- I Inf) = +-1 +- I 0
*
* ctanh(+-Inf + I y) = +-1 + I 0 sin(2y) for y finite
*
* The imaginary part of the sign is unspecified. This special
* case is only needed to avoid a spurious invalid exception when
* y is infinite.
*/
if (ix >= 0x7ff00000) {
if ((ix & 0xfffff) | lx) /* x is NaN */
return (CMPLX((x + 0) * (y + 0),
y == 0 ? y : (x + 0) * (y + 0)));
SET_HIGH_WORD(x, hx - 0x40000000); /* x = copysign(1, x) */
return (CMPLX(x, copysign(0, isinf(y) ? y : sin(y) * cos(y))));
}
/*
* ctanh(x + I NaN) = d(NaN) + I d(NaN)
* ctanh(x +- I Inf) = dNaN + I dNaN
*/
if (!isfinite(y))
return (CMPLX(y - y, y - y));
/*
* ctanh(+-huge +- I y) ~= +-1 +- I 2sin(2y)/exp(2x), using the
* approximation sinh^2(huge) ~= exp(2*huge) / 4.
* We use a modified formula to avoid spurious overflow.
*/
if (ix >= 0x40360000) { /* |x| >= 22 */
double exp_mx = exp(-fabs(x));
return (CMPLX(copysign(1, x),
4 * sin(y) * cos(y) * exp_mx * exp_mx));
}
/* Kahan's algorithm */
t = tan(y);
beta = 1.0 + t * t; /* = 1 / cos^2(y) */
s = sinh(x);
rho = sqrt(1 + s * s); /* = cosh(x) */
denom = 1 + beta * s * s;
return (CMPLX((beta * rho * s) / denom, t / denom));
}
double complex
ctan(double complex z)
{
/* ctan(z) = -I * ctanh(I * z) = I * conj(ctanh(I * conj(z))) */
z = ctanh(CMPLX(cimag(z), creal(z)));
return (CMPLX(cimag(z), creal(z)));
}