blob: 90f0cfb185b6950a179d676890d6f50eded6dd53 [file] [log] [blame]
/* Round double value to long long int.
Copyright (C) 1997 Free Software Foundation, Inc.
This file is part of the GNU C Library.
The GNU C Library is free software; you can redistribute it and/or
modify it under the terms of the GNU Lesser General Public
License as published by the Free Software Foundation; either
version 2.1 of the License, or (at your option) any later version.
The GNU C Library is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
Lesser General Public License for more details.
You should have received a copy of the GNU Lesser General Public
License along with the GNU C Library; if not, write to the Free
Software Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA
02111-1307 USA. */
#include <math.h>
/* I think that what this routine is supposed to do is round a value
to the nearest integer, with values exactly on the boundary rounded
away from zero. */
/* This routine relies on (long long)x, when x is out of range of a long long,
clipping to MAX_LLONG or MIN_LLONG. */
long long int
__llround (double x)
{
double xrf;
long long int xr;
xr = (long long int) x;
xrf = (double) xr;
if (x >= 0.0)
if (x - xrf >= 0.5 && x - xrf < 1.0 && x+1 > 0)
return x+1;
else
return x;
else
if (xrf - x >= 0.5 && xrf - x < 1.0 && x-1 < 0)
return x-1;
else
return x;
}
weak_alias (__llround, llround)
#ifdef NO_LONG_DOUBLE
strong_alias (__llround, __llroundl)
weak_alias (__llround, llroundl)
#endif