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// Copyright (c) 2001-2010 Hartmut Kaiser
//
// Distributed under the Boost Software License, Version 1.0. (See accompanying
// file LICENSE_1_0.txt or copy at http://www.boost.org/LICENSE_1_0.txt)
// The main purpose of this example is to show how a single fusion sequence
// can be filled from a parsed input of the elements in different sequences
#include <boost/config/warning_disable.hpp>
#include <boost/mpl/print.hpp>
#include <boost/spirit/include/qi.hpp>
#include <boost/fusion/include/struct.hpp>
#include <boost/fusion/include/nview.hpp>
#include <boost/foreach.hpp>
namespace fusion = boost::fusion;
namespace qi = boost::spirit::qi;
///////////////////////////////////////////////////////////////////////////////
namespace client
{
// Our employee struct
struct employee
{
std::string surname;
std::string forename;
int age;
double salary;
std::string department;
};
// define iterator type
typedef std::string::const_iterator iterator_type;
// This is the output routine taking a format description and the data to
// print
template <typename Parser, typename Sequence>
bool parse(std::string const& input, Parser const& p, Sequence& s)
{
iterator_type begin = input.begin();
return qi::parse(begin, input.end(), p, s);
}
}
// We need to tell fusion about our employee struct to make it a first-class
// fusion citizen. This has to be in global scope. Note that we don't need to
// list the members of our struct in the same sequence a they are defined
BOOST_FUSION_ADAPT_STRUCT(
client::employee,
(int, age)
(std::string, surname)
(std::string, forename)
(std::string, department)
(double, salary)
)
///////////////////////////////////////////////////////////////////////////////
// that's the different types we need to reorder the attributes
typedef fusion::result_of::as_nview<client::employee, 2, 0>::type name_and_age;
typedef fusion::result_of::as_nview<client::employee, 1, 2, 4>::type names_and_salary;
typedef fusion::result_of::as_nview<client::employee, 2, 0, 3>::type name_age_and_department;
///////////////////////////////////////////////////////////////////////////////
int main()
{
std::string str;
// some employees
client::employee john;
client::employee mary;
client::employee tom;
// print data about employees in different formats
{
// parse forename and age only
name_and_age johnview(fusion::as_nview<2, 0>(john));
bool r = client::parse(
"John, 25",
*(qi::char_ - ',') >> ", " >> qi::int_,
johnview);
if (r) {
std::cout << "Parsed: " << john.forename << ", " << john.age
<< std::endl;
}
// parse surname, forename, and salary
names_and_salary maryview(fusion::as_nview<1, 2, 4>(mary));
r = client::parse(
"Higgins, Mary: 2200.36",
*(qi::char_ - ',') >> ", " >> *(qi::char_ - ':') >> ": " >> qi::double_,
maryview);
if (r) {
std::cout << "Parsed: " << mary.forename << ", " << mary.surname
<< ", " << mary.salary << std::endl;
}
// parse forename, age, and department
name_age_and_department tomview(fusion::as_nview<2, 0, 3>(tom));
client::parse(
"Tom: 48 (Boss)",
*(qi::char_ - ':') >> ": " >> qi::int_ >> " (" >> *(qi::char_ - ')') >> ')',
tomview);
if (r) {
std::cout << "Parsed: " << tom.forename << ", " << tom.age
<< ", " << tom.department << std::endl;
}
}
// now parse a list of several employees and print them all
std::vector<client::employee> employees;
// parse surname, forename, and salary for all employees
{
qi::rule<client::iterator_type, names_and_salary()> r =
*(qi::char_ - ',') >> ", " >> *(qi::char_ - ',') >> ", " >> qi::double_;
bool result = client::parse(
"John, Smith, 2000.50\n" "Mary, Higgins, 2200.36\n" "Tom, Taylor, 3200.00\n",
r % qi::eol, employees);
std::cout << "Parsed: " << std::endl;
BOOST_FOREACH(client::employee const& e, employees)
{
std::cout << e.forename << ", " << e.surname << ", " << e.salary
<< std::endl;
}
}
return 0;
}